397^2+(r-20)^2=r^2

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Solution for 397^2+(r-20)^2=r^2 equation: 



397^2+(r-20)^2=r^2

We move all terms to the left:

397^2+(r-20)^2-(r^2)=0

determiningTheFunctionDomain
-r^2+(r-20)^2+397^2=0

We add all the numbers together, and all the variables

-1r^2+(r-20)^2+157609=0

We move all terms containing r to the left, all other terms to the right

-1r^2+(r-20)^2=-157609

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